30r^2-36=6r

Solution for 30r^2-36=6r equation:

30r^2-36=6r

We move all terms to the left:

30r^2-36-(6r)=0

a = 30; b = -6; c = -36;
Δ = b2-4ac
Δ = -62-4·30·(-36)
Δ = 4356
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4356}=66$
$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-66}{2*30}=\frac{-60}{60}
=-1
$
$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+66}{2*30}=\frac{72}{60}
=1+1/5
$